Hypothesis Testing
Based on our data collected from the DOE practical in which we manipulate 3 factors to determine which factor significantly affects the shooting distance. We will be using data from both Full Factorial and Fractional Factorial.
List of Team Members:
DOE PRACTICAL TEAM MEMBERS (fill
this according to your DOE practical):
1. Cheong Jun Weng
2. Roy Le Jing Hao
3. Beh Pei Jie
4. Cao Yongjie
5. Adam Bin Sulaiman
Data collected for FULL factorial design using
CATAPULT A
Data collected for FRACTIONAL factorial design using
CATAPULT B
Jun Weng will use Run #2 from FRACTIONAL factorial and Run#2 from FULL factorial.
Roy will use Run #3 from FRACTIONAL factorial and Run#3
from FULL factorial.
Adam will use Run #5 from FRACTIONAL factorial and
Run#5 from FULL factorial.
Yongjie will use Run #8 from FRACTIONAL factorial and
Run#8 from FULL factorial.
Pei Jie will use Run #3 from FRACTIONAL factorial and Run#3
from FULL factorial.
|
The QUESTION |
The catapult (the ones that were used in the DOE practical)
manufacturer needs to determine the consistency of the products they have manufactured.
Therefore they want to determine whether CATAPULT A produces the same flying
distance of projectile as that of CATAPULT B. |
|
Scope of the
test |
The human factor is
assumed to be negligible. Therefore different user will not have any effect
on the flying distance of projectile.
Flying distance for
catapult A and catapult B is collected using the factors below: Arm length = 28 cm Start angle = 0 degree Stop angle = 90 degree |
|
Step 1: State the
statistical Hypotheses: |
State the null hypothesis
(H0): Catapult A and Catapult B fires projectile at a similar distance. uA = uB u = distance between the landing point of projectile and catapult State the alternative
hypothesis (H1): uA ≠ uB u = distance between the landing point of projectile and catapult |
|
Step 2: Formulate an
analysis plan. |
Sample size is 8. Therefore t-test will be used.
Since the sign of H1
is ≠, a two-tailed test is used.
Significance level (α) used in this test is 0.05
|
|
Step 3: Calculate the
test statistic |
State the mean and
standard deviation of sample catapult A: mean A = 91.8 cm standard deviation A = 3.28 cm State the mean and standard deviation of sample catapult B: mean B = 90.3 cm standard deviation B = 2.84 cm Compute the value of the test statistic (t): v = 8 + 8 - 2 = 14 |
|
Step 4: Make a
decision based on result |
Type of test (check one
only) 1. Left-tailed test: [ __
] Critical value tα = - ______ 2. Right-tailed test: [ __ ] Critical value tα = ______ 3. Two-tailed test: [ ✔ ] Critical value tα/2 (0.975) = ± 2.145 Since t =
0.86 and t(0.975) = ± 2.145. Thus, - t(0.975) < t < + t(0.975)
Since t =
0.86 falls within the accepted region, hence the null hypothesis is not
rejected
Therefore Ho is not rejected |
|
Conclusion
that answer the initial question |
Based on the results, the hypothesis that catapult A and B launches the projectile at a similar distance under similar factors is true. Thus, there is not performance difference between catapult A and B. |
|
Compare your
conclusion with the conclusion from the other team members. What
inferences can you make from these comparisons? |
I have observed that my teammates agree on the null hypothesis being acceptable. However, many did not show their working or methods thus I am quite confused as to who to verify my conclusion with. Thus, I decided to compare my conclusion with some of my class mates. They all have mixed results and conclusions. Some reject while some accepts the null hypothesis. The inference I could make is that comparing conclusions with teammates added with the entire class will be more accurate. As comparing with a small group of people with similar conclusion made from carrying out a similar experiment in the same team may lead to bias. Thus, my ultimate inference is that the more data we have and share, the better our conclusions will be. |
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